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Python

def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(n):
while n > 0:
digit = n % 10
if digit % 2 == 0:
return True
n //= 10
return False
result = [num for num in x if not has_even_digit(num)]
return sorted(result)