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Python

def digits(n):
"""Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15
"""
product = 1
has_odd = False
for digit in str(n):
d = int(digit)
if d % 2 == 1:
product *= d
has_odd = True
return product if has_odd else 0