Based on my knowledge of this matplotlib issue, I understand the problem:

In matplotlib v3.6.0, the seaborn styles were renamed from `seaborn-*` to `seaborn-v0_8-*` (e.g., `seaborn-colorblind` became `seaborn-v0_8-colorblind`). The old names were deprecated but the error message doesn't help users understand this.

The fix should be in the `lib/matplotlib/style/core.py` file to:
1. Add deprecation warnings when old style names are used
2. Provide backward compatibility by mapping old names to new names

Here's the patch:

--- a/lib/matplotlib/style/core.py
+++ b/lib/matplotlib/style/core.py
@@ -43,6 +43,18 @@ BASE_LIBRARY_PATH = os.path.join(mpl.get_data_path(), 'stylelib')
 # Users may want multiple library paths, so store a list of paths.
 USER_LIBRARY_PATHS = [os.path.join(mpl.get_configdir(), 'stylelib')]
 
+# A list of rcParams that should not be applied from styles
+STYLE_BLACKLIST = {
+    'interactive', 'backend', 'backend.qt4', 'webagg.port', 'webagg.address',
+    'webagg.port_retries', 'webagg.open_in_browser', 'backend_fallback',
+    'toolbar', 'timezone', 'figure.max_open_warning',
+    'figure.raise_window', 'savefig.directory', 'tk.window_focus',
+    'docstring.hardcopy', 'date.epoch'}
+
+# Deprecated style name aliases
+STYLE_ALIASES = {f'seaborn-{s}': f'seaborn-v0_8-{s}' for s in [
+    'bright', 'colorblind', 'dark', 'dark-palette', 'darkgrid', 'deep',
+    'muted', 'notebook', 'paper', 'pastel', 'poster', 'talk', 'ticks', 'white', 'whitegrid']}
 
 def _remove_blacklisted_style_params(d, warn=True):
     to_remove = set(d) & STYLE_BLACKLIST
@@ -125,6 +137,13 @@ def use(style):
             style = style.read()
         if isinstance(style, str):
             style = _rc_params_in_file(style, fail_on_error=True)
+        elif style in STYLE_ALIASES:
+            _api.warn_deprecated(
+                '3.6', name=style, alternative=STYLE_ALIASES[style],
+                obj_type='style')
+            style = library[STYLE_ALIASES[style]]
+        elif style in library:
+            style = library[style]
         return dict(style)
 
     def update_nested_dict(old_dict, new_dict):

Wait, I need to reconsider. Looking at the actual structure of the style handling code, the fix should be different. Let me provide a more accurate patch that handles the deprecated style names properly:

--- a/lib/matplotlib/style/core.py
+++ b/lib/matplotlib/style/core.py
@@ -43,6 +43,12 @@ BASE_LIBRARY_PATH = os.path.join(mpl.get_data_path(), 'stylelib')
 # Users may want multiple library paths, so store a list of paths.
 USER_LIBRARY_PATHS = [os.path.join(mpl.get_configdir(), 'stylelib')]
 
+# Mapping of deprecated style names to their replacements
+STYLE_ALIASES = {
+    **{f'seaborn-{s}': f'seaborn-v0_8-{s}'
+       for s in ['bright', 'colorblind', 'dark', 'dark-palette', 'darkgrid',
+                 'deep', 'muted', 'notebook', 'paper', 'pastel', 'poster',
+                 'talk', 'ticks', 'white', 'whitegrid']}}
 
 def _remove_blacklisted_style_params(d, warn=True):
     to_remove = set(d) & STYLE_BLACKLIST
@@ -113,6 +119,12 @@ def use(style):
 
     def _apply_style(style_name, in_cfg_file=False):
         if isinstance(style_name, str):
+            if style_name in STYLE_ALIASES:
+                _api.warn_deprecated(
+                    '3.6', name=style_name, obj_type='style',
+                    alternative=STYLE_ALIASES[style_name])
+                style_name = STYLE_ALIASES[style_name]
+
             if style_name in library:
                 style = library[style_name]
             elif style_name == 'default':